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x^2-7=-x+7
We move all terms to the left:
x^2-7-(-x+7)=0
We add all the numbers together, and all the variables
x^2-(-1x+7)-7=0
We get rid of parentheses
x^2+1x-7-7=0
We add all the numbers together, and all the variables
x^2+x-14=0
a = 1; b = 1; c = -14;
Δ = b2-4ac
Δ = 12-4·1·(-14)
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{57}}{2*1}=\frac{-1-\sqrt{57}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{57}}{2*1}=\frac{-1+\sqrt{57}}{2} $
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